x^2-4x+29=3

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Solution for x^2-4x+29=3 equation:


Simplifying
x2 + -4x + 29 = 3

Reorder the terms:
29 + -4x + x2 = 3

Solving
29 + -4x + x2 = 3

Solving for variable 'x'.

Reorder the terms:
29 + -3 + -4x + x2 = 3 + -3

Combine like terms: 29 + -3 = 26
26 + -4x + x2 = 3 + -3

Combine like terms: 3 + -3 = 0
26 + -4x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-26' to each side of the equation.
26 + -4x + -26 + x2 = 0 + -26

Reorder the terms:
26 + -26 + -4x + x2 = 0 + -26

Combine like terms: 26 + -26 = 0
0 + -4x + x2 = 0 + -26
-4x + x2 = 0 + -26

Combine like terms: 0 + -26 = -26
-4x + x2 = -26

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -26 + 4

Reorder the terms:
4 + -4x + x2 = -26 + 4

Combine like terms: -26 + 4 = -22
4 + -4x + x2 = -22

Factor a perfect square on the left side:
(x + -2)(x + -2) = -22

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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